Taking the example of `Al_(2)(SO_(4))_(3)`, derive the relation between molar conductivity and equivalent conductivity.

Explanation

To derive the relation between molar conductivity (Λ_m) and equivalent conductivity (Λ_e) using the example of \( Al_2(SO_4)_3 \), we will follow these steps:

### Step 1: Define Molar Conductivity and Equivalent Conductivity
Molar conductivity (Λ_m) is defined as the conductivity (κ) of an electrolyte solution multiplied by 1000 and divided by the molarity (C) of the solution:
\[ \Lambda_m = \frac{\kappa \times 1000}{C} \]
Equivalent conductivity (Λ_e) is defined as the conductivity (κ) multiplied by 1000 and divided by the normality (N) of the solution:
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