Why electrolysis of NaBr and NaI gives `Br_(2)` and `I_(2)` respectively while that of `NaF` gives `O_(2)` instead of `F_(2)`?

Explanation

To understand why the electrolysis of NaBr and NaI produces Br₂ and I₂ respectively, while the electrolysis of NaF produces O₂ instead of F₂, we can analyze the oxidation potentials of the halide ions (Br⁻, I⁻, and F⁻) in comparison to water.

### Step-by-Step Solution:

1. **Understanding Electrolysis**:
- Electrolysis involves the breakdown of a compound into its elements or simpler compounds using electricity. In the case of sodium halides (NaBr, NaI, NaF), the electrolysis occurs in an aqueous solution.

2. **Identifying the Anions**:
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