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The resistance of a conductivity cell co...

The resistance of a conductivity cell containing 0.001 M KCl solution at 298K is 1500 `Omega`. What is the cell constant if conductivity of 0.001 M KCl solution at 298K is 0.146`xx10^(-3)"S "cm^(-1)`?

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To find the cell constant of a conductivity cell containing a 0.001 M KCl solution, we can use the relationship between conductivity (κ), resistance (R), and the cell constant (K). The formula we will use is: \[ K = \kappa \times R \] Where: - \( K \) is the cell constant (in cm\(^{-1}\)), - \( \kappa \) is the conductivity (in S cm\(^{-1}\)), - \( R \) is the resistance (in ohms). ...
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(a) Define the following terms. (i) Primary batteries (ii) Corrosion (b) The resistance of a conductivity cell containing 0.001" M KCl" solution at 298 K is 1500Omega. What is the cell constant if conductivity of 0.001" M KCl" solution at 298 K is 0.146xx10^(-3)Scm^(-1) ?

The resistance of a conductivity cell contaning 0.001M KCl solution at 298K is 1500Omega . What is the cell constant if conductivity of 0.001M KCl solution at 298K is 0.146 xx 10^(-3)S cm^(-3) S cm^(-1) .

(a) Define molar conductivity of a solution and explain how molar conductivity changes with change in concentration of solution for a weak and a strong electrolyte. (b) The resistance of conductivity cell containing 0.001 M KCl solution at 298 K is 1500 omega . What is the cell constant if the conductivity of 0.001 MKCl solution at 298 K is 0.146 xx 10^(-3) S cm^(-1)