Use the data given in Q.8 and find out the most stable ion in its reduced form.

Options

A. `Cl^(-)`
B. `Cr^(3+)`
C. `Cr`
D. `Mn^(2+)`

Answer

D

Explanation

`E_(red)^(@)` is highest for `MnO_(4)^(-)//Mn^(2+)`. This shows that this reduction takes place most easiliy. Hence, `Mn^(2+)` will be most stable ion in the reduced form.