The quantity of charge required to obtain one mole of aluminium from `Al_(2)0_(3)` is

Options

A. 1F
B. 6F
C. 3F
D. 2F

Answer

C

Explanation

`Al_(2)O_(3) to 2Al,` i.e., `2Al^(3+)+6e^(-)to2Al` or `Al^(3+)+3e^(-)toAl`. Hence to obtain one mole of Al. charge requried=3F.