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wedge^(@)m[NH(4)OH] is equal to...

`wedge^(@)m[NH_(4)OH]` is equal to ____

A

`wedge_(m(NH_(4)OH))^(0)+wedge_(m(NH_(4)Cl))^(0)-wedge_((HCl))^(0)`

B

`wedge_(m(NH_(4)Cl))^(0)+wedge_(m(NaOH))^(0)-wedge_((NaCl))^(0)`

C

`wedge_(m(NH_(4)Cl))^(0)+wedge_(m(NaCl))^(0)-wedge_((NaOH))^(0)`

D

`wedge_(m(NaOH))^(0)+wedge_(m(NaCl))^(0)-wedge_((NH_(4)Cl))^(0)`

Text Solution

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The correct Answer is:
B
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