Home
Class 12
CHEMISTRY
Conductivity kappa, is equal to...

Conductivity `kappa`, is equal to ____

A

`(1)/(R)(l)/(A)`

B

`(G^(**))/(R)`

C

`wedge_(m)`

D

`(l)/(A)`

Text Solution

Verified by Experts

The correct Answer is:
B

`R=rho.(1)/(A)` or `R=(1)/(kappa)(1)/(A)` or `kappa`(conductivity)`=(1)/(R)(1)/(A)`, i.e., (a)
As `(1)/(A)=G^(@)` (cell constant), `kappa(1)/(R)G^(@)=(G^(**))/(R)` , i.e., (b)`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    PRADEEP|Exercise NCERT EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS (MATCHING TYPE QUESTIONS)|3 Videos
  • ELECTROCHEMISTRY

    PRADEEP|Exercise NCERT EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS (ASSERTION AND REASON TYPE QUESTIONS)|10 Videos
  • ELECTROCHEMISTRY

    PRADEEP|Exercise NCERT EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS (MULTIPLE QUESTIONS-I)|39 Videos
  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise IMPORTANT QUESTIONS|30 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    PRADEEP|Exercise Curiosity Questions|2 Videos

Similar Questions

Explore conceptually related problems

Conductivity k, is equal to ......

Conductivity k, is equal to ....

Conductivity k, is equal to

Conductivity k, is equal to …………. 1) 1/R. l/A 2) G/A 3) Lambda_(m) 4) l/A

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation : kappa=c xx l/A where, c=1//R is the conductance and l//A is the cell constant. Molar conductance (Lambda_(m)) and equivalence conductance (Lambda_(e)) of an electrolyte solution are calculated using the following similar relations : Lambda_(m)= kappa xx 1000/M Lambda_(e)= kappa xx 1000/N Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : Lambda_(m)=Lambda_(m)^(@)-b sqrt(c) where, Lambda_(m)^(@)= molar conductance at infinite dilution c= concentration of the solution b= constant The degrees of dissociation of weak electrolytes are calculated as : alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@) The conductance of a solution of an electrolyte is equal to that of its specific conductance. The cell constant of the conductivity cell is equal to :

The conductance of a solution of an electrolyte is equal to that of its specific conductance The cell constant of the conductivity cell is equal to

Conductivity (kappa) of any conducting material is defined as the