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The standard reduction potential for two...

The standard reduction potential for two reactions are given below
`AgCl(s)+e^(-)rarrAg(s)+Cl^(-)(aq) ,E^(@)=0.22V`
`Ag^(+)(aq)+e^(-)rarrAg(s),E^(@)=0.80V`
The solubility product of AgCl under standard conditions of temperature is given by

A

`1.6xx10^(-5)`

B

`1.5xx10^(-8)`

C

`3.2xx10^(-10)`

D

`1.5xx10^(-10)`

Text Solution

Verified by Experts

The correct Answer is:
D
Subtracting second eqn. from first eqn. we get
`AgCl(s)hArrAg^(+)(aq)+Cl^(-)(aq),E^(@)=-0.58V`
Applying Nernst eqn,
`E=E^(@)-(0.0591)/(1)"log"([Ag^(+)][Cl^(-)])/([AgCl(s)])`
Putting `[AgCl(s)]=1` and at equilibrium E=0
`E^(@)=0.0591log[Ag^(+)][Cl^(-)]=0.0591logK_(sp)`
or `-0.58=0.0591logK_(sp)`
`logK_(sp)=-9.8139=overline(10).1861`
`K_(sp)=1.535xx10^(-10)`
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