Home
Class 12
CHEMISTRY
If the 0.05 molar solution of M^+ is rep...

If the 0.05 molar solution of `M^+` is replaced by a 0.0025 Molar `M^+` solution. then the magnitude of the cell potential would be :

A

35 mV

B

70 mV

C

140 mV

D

700 mV

Text Solution

Verified by Experts

The correct Answer is:
C
From the above equation,
`(2.303RT)/(F)"log(1)/(0.05)=70mV`
`=70xx10^(-3)V=0.07V`
`therefore(2.303RT)/(F)(1.301)=0.07`
or `(2.303RT)/(F)=(0.07)/(1.301)=0.0538`
For the new concentration,
`E_(cell)=(2.303RT)/(F)"log"(1)/(0.0025)`
`=0.0538log400=0.0538xx2.6021`
`=0.140V=140mV`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    PRADEEP|Exercise VALUE BASED QUESTIONS WITH ANWER (Matching Type Question)|4 Videos

  • ELECTROCHEMISTRY

    PRADEEP|Exercise VALUE BASED QUESTIONS WITH ANWER (Matrix-Type Questions)|2 Videos

  • ELECTROCHEMISTRY

    PRADEEP|Exercise VALUE BASED QUESTIONS WITH ANWER (Multiple Choice Questions-II)|7 Videos

  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise IMPORTANT QUESTIONS|30 Videos

  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    PRADEEP|Exercise Curiosity Questions|2 Videos

Similar Questions

Explore conceptually related problems

The concentration of potassium ions inside a biological cell is at least 20 times higher than outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simplel model for a concentration cell involving a metal M is M(s)|M^(o+)(aq,0.05 molar )||M^(o+)(aq,1 molar )|M(s) For the abov electrolytic cell, the magnitude of the cell potential is |E_(cell)|=70mV. If the 0.05 moolar solution of M^(o+) is replaced by a 0.0025 molar M^(o+) solution, then the magnitude of the cell potential would be

If the 0.05 molar solution of M^+ is replaced by a 0.0025 molar solution, then the magnitude of the cell potential would be :

What is the pH of a 0.025 M solution of KOH ?

2.5 litre of 1 M NaOH solution are mixed with another 3 litre of 0.5 M NaOH solution Then the molarity of the resulting

The degree of hydrolysis of salt of weak acid and weak base in its 0.1M solution is found to be 5%. If the molarity of the solution of same salt is 0.5 M, then the percentage degree of hydrolysis of the salt should be :-