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All the energy released from the reactio...

All the energy released from the reaction `XrarrY,Delta_(r)G^(@)=-193kJ"mol"^(-1)` is used for oxidising `M^(@)` as `M^(+)rarrM^(3+)+2e^(-),E^(@)=-0.25V`.
Under standard conditions, the number of moles of `M^(+)`oxidised when one mole of X is converted to Y is `[F=96500C "mol"^(-1)]`

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The correct Answer is:
D

`XtoY,Delta_(r)G^(@)=-193" kJ "mol^(-1)` . . . (i)
`M^(+)toM^(3+)+2e^(-),E^(@)=-0.25V`
For this reaction, `DeltaG^(@)=-nFE^(@)`
`=-2xx96500xx(-0.25)=48250" J "mol^(-1)`
`=48.25" kJ "mol^(-1)`
i.e., 48.25 kJ of energy is used for oxidizing 1 mole of `M^(+) ` to `M^(3+)`
`therefore` No. of moles of `M^(+)` oxidized by 193 kJ of energy `=(193)/(48.25)=4`
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