The number of moles of `KMnO_(4)` that will be needed to react completely with one mole of ferrous oxalate in acidic solution is:

Explanation

`2KMnO_(4)+ 3H_(2)SO_(4) rarr K_(2)SO_(4)+ 2MnSO_(4) +3H_(2)O+ 5(O)] xx3`
`FeC_(2)O_(4) + H_(2)SO_(4) rarr FeSO_(4)+ H_(2)C_(2)O_(4)] xx 10`
` 2FeSO_(4)+ H_(2)SO_(4) + (O) rarr Fe_(2)(SO_(4))_(3)+ H_(2)O] xx 5`
`H_(2)C_(2)O_(4) + (O) rarr 2CO_(2)+ H_(2)O] xx 10`
`bar (6 KMnO_(4) + 24 H_(2)SO_(4) + 10 FeC_(2)O_(4) rarr 3K_(2)SO_(4) + 6 MnSO_(4) + 5Fe_(2)(SO_(4))_(3)+ 20 CO_(2)+ 24 H_(2)O)`
Thus, 10 moles of ferrous oxalate reacts with 6 moles of `KMnO_(4)`
`:. ` 1 mole of ferrous oxalate will react with `KMnO_(4)= ( 6)/(10) ` mole `= (3)/( 5) ` mole