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Although +3 oxidation stae is thje chara...

Although +3 oxidation stae is thje characteristic oxidation state of lanthanoids but cerium shows +4 oxidation state also. Why ?

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`._(58) Ce= [Xe]^(54) 4f^(2) 5d^(0) 6s^(2) . Ce^(3+) = [Xe]^(54) 4f^(1) `. Further loss of one electron gives stable `4f^(0)` configuration. Hence, it shows `+4` oxidation state also.
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