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Four successive members of the first row...

Four successive members of the first row transition elements are listed below with atomic numbers. Which one of them is expected to have the highest `E_(M^(3+)//M^(2+))^(0)` value

A

`Co(Z= 27)`

B

`Cr(Z= 24)`

C

`Mn(Z=25)`

D

`Fe(Z= 26)`

Text Solution

Verified by Experts

Highest `E_(M^(3+) //M^(2+))^(@)` value means highest reduction potential increases from left to right along the period in d-block but there are some exceptions. `Cr^(3+)` is more stable than `Cr^(2+)`. `Fe^(3+)(3d^(5))` is more stable than `Fe^(3+)` but `Mn^(2+)(3d^(5))` is more stable than `Mn^(3+)` but `Co^(2+)` ionsare still more stable than `Co^(3+)` in aqueous solution as`Co^(3+)` are easily reduced to`Co^(2+)` by `H_(2)O` . Hence, `Co^(3+) // Co^(2+)` has highest reduction potential
`(E_(Cr^(3+)//Cr^(2+))^(@)= -0.41V, E_(Mn^(3+ ) //Mn^(2+))^(@)= + 1.57V,E_(Fe^(3+) //Fe^(2+))^(@)= + 0.77V, E_(Co^(3+) //Co^(2+))^(@)= 1.97V)`
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