The `E^(0)(M^(2+)//M)` value for copper is positive `(+0.34V)`. What is possibly the reason for this?

The E(Theta)(M^(2+)//M) Value for copper is positive (+0.34V) . What is possibly the statement-2 for this?

If the standard electrode poten tial of Cu^(2+)//Cu electrode is 0.34V. What is the electrode potential of 0.01 M concentration of Cu^(2+) ?

The E^(@) value of Zn is -0.76 V while that of Cu is +0.34 V. Do these values help in locating the relative positions of the electrodes in the electrochemical series ?

{:(E_(M^(2+)//M)^(@),Cr,Mn, Fe, Co, Ni, Cu),(,-0.91,-1.18,-0.44,-0.28,-0.25,+0.34):} From the given data of E^(@) values, answer the following questions : (i) Why is E_((Cu^(2+)//Cu))^(@) value exceptionally positive ? (ii) Why is E_((M^(2+)//M))^(@) vlue highly negative as compared to other elements ? (iii) Which is a stronger reducing agent , Cr^(2+) or Fe^(2+) ? Give reason.

Ag^(+)(aq)+e^(-)rarrAg(s) E^(@)=0.80V Cu^(2+)(aq)+2e^(-)rarrCu(s) E^(@)=0.34V Which expression gives the voltage for this cell if [Cu^(2+)]=1.00M and [Ag^(+)]=0.010M ?

An electrochemical cell constructed for the reaction : Cu^(2+)(aq) + M(s) rightarrow Cu(s) + M^(2+) (aq) has an E^(@) = 0.75V . The standard reduction potential for Cu^(2+)(aq) is 0.34V. What is the standard reduction potential for M^(2+) (aq)?