In a class,there are 15 boys and 10 girls.Three students are selected at random,Find the probability that one girl and two boys are selected

Explanation

Here, the total number of students ` = 15+10 = 25`

So, number of ways selecting 3 students, `n(S) = C(25,3)`.

Number of ways selecting one girl and two boys `n(E) = C(10,1)xxC(15,2)`

`:.` Probability of selecting one girl and two boys, `P(E) = (n(E))/(n(S))`

`P(E) = (C(10,1)xxC(15,2))/(C(25,3))`

`P(E) = (10**15**14/2)/((25**24**23)/(3**2)) = 1050/2300 = 21/46`