`[6x+1]/3`+1=`[x-3]/6`

Solve : (6x+1)/(2)+1=(7x-3)/(3)

Let f(x) = 6x^(4//3) - 3x^(1//3) defined on [-1,1] then

Find the derivative dy/dx of the function y=((1-2x)^(2//3)(1+3x)^(-3//4))/((1-6x)^(5//6)(1+7x)^(-6//7)).

If int (x^9+x^6+x^3)(2x^6+3x^3+6)^(1/3) dx=1/a(2x^9+3x^6+6x^3)^(4/3)+c , then 'a' is equal to:

If int (x^9 + x^6 + x^3)(2x^6 + 3x^3 + 6)^(1/3) dx = 1/a (2x^9 + 3x^6 + 6x^3)^(4/3) + c , then the value of a/4 must be

If x=(1)/(3)+(1.3)/(3.6)+(1.3.5)/(3.6.9)+…. , then x^2+2x-2=

If (5x)/4 +(6-x)/8 = (6(x+3))/3-1/6 then x = ?

lim_(x rarr0)((1-cos6x)^(2))/(6x tan3x-3x tan6x)=