A long horizontal wire `P` carries of `50 A`. It is rigidly fixed. Another fine wire `Q` is placed directly above and parallel to `P`. The wieght of wire `Q` is `0.075 N//m` and carries a current of `25 A`. Find the position of wire `Q` from `P` so that the wire `Q` remains suspended due to magnetic repulsion.

A long horizontal wire P carries a current of 50A. It is rigidly fixed. Another wire Q is placed directly above and parallel to P, as shown in figure below. The weight per unit length of the wire Q is 0.025 Nm^(-1) and it carries a current of 25A. Find the distance .r. of the wire Q from the wire P so that the wire Q remains at rest.

A long horizontally fixed wire carries a current of 100 A directly above and parallel to it is a fine wire that carries a current of 20 A and weight 0.04 N/m The distance between the two wires for which the upper wire is just supported by magnetic repulsion is

A long horizontally fiexed wire carries a current of 100 A directely above and parallel to it is a fine wire that carries a current of 20 A and weight 0.04 N/m The distance between the two wires for which the upper wire is just supported by magnetic repulsion is

A long horizontal rigidly supported wire carries a current i_a of 100 A. Directly above it and parallel to its is a fine wire that carries a current i_b of 20 A and weighs 0.073 N/m. How far above the lower wire should the second wire be kept if we wish to support it by magnetic repulsion? Given permeability constant mu_0= 4pi xx 10^-7 Wb A^-1m^-1 .

P, Q and R long parallel straight wires in air, carrying currents as shown. The direction of resultant force on R is :-