A capacitor when filled with a dielectric `K = 3` has charge `Q_(0)`, voltage `V_(0)` and filed `E_(0)`. If the dielectric is replaced with another one having `K = 9` the new values of charge, voltage and field will be respectively

A capacitor when filled with a dielectric k = 3 has charge Q_(0) , voltage V_(0) and field E_(0) . After disconnecting the battery, if the dielectric is replaced with another one having k = 9, the new values of charge voltage and field are ,

A parallel plate capacitor filled with a dielectric of relative permittivity 5 between its plates is charged to acquire an energy E and isolated. If the dielectric is replaced by another of relative permittivity 2, its energy becomes

A parallel plate capacitor filled with a material of dielectric constant K is charged to a certain voltage and is isolated. The dielectric material is removed. Then (a) The capacitance decreases by a factor K (b) The electric field reduces by a factor K (c ) The voltage across the capacitor increases by a factor K (d) The charge strored in the capacitor increases by a factor K

A parallel plate capacitor filled with a material of dielectric constant K is charged to a certain voltage and is isolated. The dielectric material is removed. Then (a) The capacitance decreases by a factor K (b) The electric field reduces by a factor K ( c) The voltage across the capacitor increases by a factor K (d) The charge stored in the capacitor increases by a factor K .

A parallel plate capacitor with a dielectric slab with dielectric constant k= 3 filling the space between the plates is charged to potential V and isolated. Then the dielectric slab is drawn out and another dielectric slab of equal thickness but dielectric constant k'= 2 is introduced between the plates. The ratio of the energy stored in the capacitor later to that initially is:

A parallel plate capacitor A is filled with a dielectric whose dielectric constant varies with applied voltage as K = V. An identical capacitor B of capacitance C_0 with air as dielectric is connected to voltage source V_0 = 30V and then connected to the first capacitor after disconnecting the voltage source. The charge and voltage on capacitor.

A parallel plate capacitor having a separation between the plates d, plate area A and material with dielectric constant K has capacitance C_(0) . Now one-third of the material is replaced by another material with dielectric constant 2K, so that effectively there are two capacitors one with area 1/3A, dielectric constant 2K and another with area 2/3A and dielectric constant K. If the capacitance of this new capacitor is C then (C)/(C_(0) is

A parallel plate capacitor has a dielectric slab of dielectric constant K between its plates that covers 1//3 of the area of its plates, as shown in the figure. The total capacitance of the capacitor is C while that of the portion with dielectric in between is C_1 . When the capacitor is charged, the plate area covered by the dielectric gets charge Q_1 and the rest of the area gets charge Q_2 . The electric field in the dielectric is E_1 and that in the other portion is E_2 . Choose the correct option/options, ignoring edge effects.