In an AP, it is given that `S_(5) + S_(7) = 167 "and" S_(10) = 235`, then find the AP, where `S_(n)` denotes the sum of its first n terms.

In an A.P. find S_(n) where a_(n) = 5n-1 . Hence find the sum of the first 20 terms.

If in an AP, S_(n)= q n^(2) and S_(m)= qm^(2) , where S_(r ) denotes the sum of r terms of the AP, then S_(q) equals to,

In an A.P. given that the first term (a) = 54, the common difference (d) = -3 and the n^(th) term (a_(n))=0 , find n and the sum of first n terms (S_(n)) of the A.P.

In an A.P. given that the first term (a) = 54, the common difference (d) = -3 and the n^(th) term (a_(n))=0 , find n and the sum of first n terms (S_(n)) of the A.P.

If in an A.P. S_(n) = qn^(2) and S_(m) = qm^(2) , where S_(r ) denotes the sum of r terms of the A.P. , then S_(q) equals :

In an A.P., S_(m) = n and S_(n) = m also m gt n ,find the sum of first (m-n) terms .

in an A.PS_(4)=16,S_(6)=-48 (where S_(n) denotes the sum of first n term of A.P then S_(10) is equal to

Let S_(n) denote the sum of first n terms of an A.P. If S_(4) = -34 , S_(3) = - 60 and S_(6) =- 93 , then the common difference and the first term of the A.P. are respectively.

If in an AP, S_(n)= qn^(2) and S_(m) =qm^(2) , where S_(r) denotes the of r terms of the AP , then S_(q) equals to