If `cotalpha + tanalpha = m` and `1/cos alpha -cos alpha=n`, then

If a cos^3 alpha +3acosalpha*sin alpha = m and a sin^3alpha +3a cos^3alpha sin^3alpha = n then (m + n)^(2/3) + (m-n)^(2/3)

If a cos^3 alpha +3acosalpha*sin alpha = m and a sin^3alpha +3a cos^3alpha sin^3alpha = n then (m + n)^(2/3) + (m-n)^(2/3)

If a cos^(3)alpha+3a cos alpha sin^(2)alpha=m and a sin^(2)alpha+3a cos^(2)alpha sin alpha=n then (m+n)^((2)/(3))+(m-n)^((2)/(3))=

If a cos^(3)alpha+3a cos alpha sin^(2)alpha=ma sin^(3)alpha+3a cos^(2)alpha sin alpha=n, then (m+n)^((2)/(3))+(m-n)^((2)/(3))=

If m cos(theta+alpha)=n cos(theta-alpha), then (m-n)cot alpha=

If m cos(theta+alpha)=n cos(theta-alpha), then (m-n)cot alpha=

If tanalpha=1/7 and tanbeta=1/3 , then cos 2alpha=

If alpha is acute angle and 2sin^(2)alpha+15cos^(2)alpha=7 , then cotalpha equal to

If A_(alpha)=[cos alpha sin alpha-sin alpha cos alpha], then prove that (A_(alpha))^(n)=[cositive in n alpha-s in n alpha cos n alpha] for every positive integer n.

1/(cos alpha + cos 3 alpha)+ 1/(cos alpha + cos 5 alpha)+ 1/(cos alpha + cos 7 alpha) +....+ 1/(cos alpha +cos(2n+1) alpha) = 1/2 "cosec" alpha[tan (n+1) alpha - tan alpha ]