Home
Class 12
MATHS
((x-4)^(2005)dot(x+8)^(2008)(x+1))/(x^(2...

`((x-4)^(2005)dot(x+8)^(2008)(x+1))/(x^(2006)(x-2)^3dot(x+3)^5 0(x-6)(x+9)^(2010))lt=0`

Promotional Banner

Similar Questions

Explore conceptually related problems

Consider the inequations: ((x-4)^(2005)dot(x+8)^(2008)(x+1))/(x^(2006)(x-2)^3dot(x+3)^5dot(x-6)(x+9)^(2010))lt=0 and 2+3/(x+1)>2/x The interval(s) which cannot be the solution of the given inequations is/are (1, 2) (b) (-2,-1) (0,1) (d) [4,6]

Consider the inequations: ((x-4)^(2005)dot(x+8)^(2008)(x+1))/(x^(2006)(x-2)^3dot(x+3)^5dot(x-6)(x+9)^(2010))lt=0 and 2+3/(x+1)>2/x Number of positive integers satisfying both the inequations are 1 (b) 2 (c) 3 (d) 5

((x-4)^(2005)*(x+8)^(2008)(x+1))/(x^(2006)(x-2)^(3)*(x+3)^(5)0(x-6)(x+9)^(2010))<=0

((x-4)^(2005)*(x+8)^(2008)*(x+1))/(x^(2006)(x-2)^(3)(x+3)^(5)*(x-6)(x+9)^(2010))<0

Solve (2x-3)/(x-1)+1=(9x-x^2-6)/(x-1)dot

Solve (2x-3)/(x-1)+1=(9x-x^2-6)/(x-1)dot

Solve (2x-3)/(x-1)+1=(6x-x^2-6)/(x-1)dot

Solve (2x-3)/(x-1)+1=(6x-x^2-6)/(x-1)dot

For x!=0,+-1, the expression (((1)/(x^(2007))-(1)/(x^(2009)))/((1)/(x^(2008))-(1)/(x^(2010)))) is

The coefficient of x^1007 in the expansion (1+x)^(2006)+x(1+x)^(2005)+x^2(1+x)^(2004)x^3(1+x)^(2003)+..... +x^(2006) is