A partical moves in a straight line with a velocity given by `(dx)/(dt)=x+1` (x is the distance described). The time taken by a particle to traverse a distance of 99 metres, is

A particle moves in a st. line with a velocity given by (dx)/(dt)=x+1 , (x is the distacne descirbed) . The time taken by a prticle to transverse a distance of 99 metres is :

A particle starts from origin with a velocity (in m/s) given by the equation (dx)/(dt) = x+ 1 . The time (in second) taken by the particle to traverse a distance of 24 m is

A particle moves in a line with velocity given by (ds)/(d t) = s+1 . The time taken by the particle to cover a distance of 9 metre is

A particle moves in a line with velocity given by (ds)/(dt)=s+1. The time taken by the particle to cover a distance of 9 metre is (A) 1 (B) log10(C)2log10(D)10

The velocity v of a particle at any instant t moving in a straight line is given by v=s +1 where s meter is the distance travelled in t second what is the time taken by the particle to cover a distacne of 9m ?

A particle moves along a horizontal straight line with a velocity-time relationship as shown in the figure-1.129. The total distance moved by the particle is :

A particle moving along a straight line has the relation s =t^2 +3, connecting the distance s described by the particle in time 1. Find the velocity and acceleration of the particle at t=4 seconds.