g(x)={[k sqrt(x+1),,0<=x<=3],[mx+2,,3

If f(x)={{:(,(sqrt(x+1)-1)/(sqrtx),"for "x ne 0),(,k, for x=0):} and f(x) is continuous at x=0, then the value of k is

Let g(x)=sqrt(x-2k), AA 2k le x lt 2(k+1) where, k in l , then

Let g(x)=sqrt(x-2k), AA 2k le x lt 2(k+1) where, k in l , then

Let g(x)=sqrt(x-2k),AA2k<=x<2(k+1) where k in integer.Check whether g(x) is periodic or not.

Let g(x)=sqrt(x-2k),AA2klt=x<2(k+1), where k in integer. Check whether g(x) is periodic or not.

Let g(x)=sqrt(x-2k),AA2klt=x<2(k+1), where k in integer. Check whether g(x) is periodic or not.

Let g(x)=sqrt(x-2k),AA2klt=x<2(k+1), where k in integer. Check whether g(x) is periodic or not.

Let g(x)=sqrt(x-2k),AA2klt=x<2(k+1), where k in integer. Check whether g(x) is periodic or not.

Let g(x)=sqrt(x-2k),AA2klt=x<2(k+1), where k in integer. Check whether g(x) is periodic or not.