" v) "sec theta-1=(sqrt(2)-1)tan theta

Solve sec theta-1=(sqrt(2)-1) tan theta .

Solve sec theta-1=(sqrt(2)-1) tan theta .

Solve sec theta-1=(sqrt(2)-1) tan theta .

General solution of the equation sec theta-1=(sqrt(2)-1)tan theta is given by.

IF cos theta ne 0, and sec theta-1=(sqrt2-1) tan theta then theta=

If ("sec" theta 1)- (sqrt(2)-1) "tan" theta, "then" theta =

For theta_(1), theta_(2), ...., theta_(n) in (0, pi/2) , if In (sec theta_(1)-tan theta_(1))+ "In" (sec theta_(2)-tan theta_(2))+...+"In" (sec theta_(n)-tan theta_(n))+ "ln" pi=0 , then the value of cos((sec theta_(1)+ tan theta_(1))(sec theta_(2)+tan theta_(2))....(sec theta_(n)+tan theta_(n))) is equal to

For theta_(1), theta_(2), ...., theta_(n) in (0, pi/2) , if In (sec theta_(1)-tan theta_(1))+ "In" (sec theta_(2)-tan theta_(2))+...+"In" (sec theta_(n)-tan theta_(n))+ "ln" pi=0 , then the value of cos((sec theta_(1)+ tan theta_(1))(sec theta_(2)+tan theta_(2))....(sec theta_(n)+tan theta_(n))) is equal to

For theta_(1), theta_(2), ...., theta_(n) in (0, pi/2) , if ln(sec theta_(1)-tan theta_(1))+ "ln" (sec theta_(2)-tan theta_(2))+...... +"ln" (sec theta_(n)-tan theta_(n))+"ln" pi=0 , then the value of cos((sec theta_(1)+ tan theta_(1))(sec theta_(2)+tan theta_(2))....(sec theta_(n)+tan theta_(n))) is equal to