Tangents are drawn to the ellipse `x^2/9+y^2/5 = 1` at the end of latus rectum. Find the area of quadrilateral so formed

Tangents are drawn to the ellipse x^(2)/9+y^(2)/5=1 at the ends of latus rectum. The area of the quadrilateral formed, is

Tangents are drawn to the ellipse (x^2)/(9)+(y^2)/(5)=1 at the ends of both latusrectum. The area of the quadrilateral so formed is

Tangents are drawn to the ellipse (x^2)/(25) + (y^2)/(16) = 1 at all the four ends of its latusrectum. Then, the area (in sq units) of the quadrilateral formed by these tangents is

Tangents are drawn to the ellipse 5x^(2)+ 9y^(2)=45 at the four ends of two latera recta. The area (in square unit) of the quadrilateral so formed is-

Find the equation of the tangent and normal to the ellipse 9x^2+16y^2=144 at the end of the latus rectum in the first quadrant.

The tangent to the ellipse (x^(2))/(25)+(y^(2))/(16)=1 at the end of the latus rectum, in the second quadrant, meets the coordinate axes at

The equations of the tangents to the ellipse 9x^(2)+16y^(2)=144 at the ends of the latus rectum are