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[" An object,moving with a speed of "6.2...

[" An object,moving with a speed of "6.25m/s" ,is "],[" decelerated at a rate given by "(dv)/(dt)=-2.5sqrt(v)/v^(2)],[" where vis the instantaneous speed.The time taken "],[" by the object,to come to rest,would be :- "(y)/(3/2)],[[" (1) "4s^(x)," (2) "8s],[" (3) "1s," (4) "2s]]

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