[" A nucleus "X" initially at rest,undergoes "],[" alpha decay according to the equation "],[232X rarr%Y+alpha" What fraction of the total "],[" energy released in the decay will be the "],[" kinetic energy of the alpha particle "]

A nucleus X initially at rest, undergoes alpha decay according to the equation _Z^232Xrarr_90^AY+alpha What fraction of the total energy released in the decay will be the kinetic energy of the alpha particle?

A nucleus X initially at rest, undergoes alpha decay according to the equation _Z^232Xrarr_90^AY+alpha What fraction of the total energy released in the decay will be the kinetic energy of the alpha particle?

A nucleus X, initially at rest, undergoes alpha-decay according to the equation. _92^AXrarr_Z^228Y+alpha (a) Find the values of A and Z in the above process. (b) The alpha particle produced in the above process is found in move in a circular track of during the process and the binding energy of the parent nucleus X. Given that m(Y)=228.03u , m( _0^1n)=1.009u m( _2^4He)=4.003u , m( _1^1H)=1.008u

A nucleus X, initially at rest, undergoes alpha-decay according to the equation. _92^AXrarr_Z^228Y+alpha (a) Find the values of A and Z in the above process. (b) The alpha particle produced in the above process is found in move in a circular track of during the process and the binding energy of the parent nucleus X. Given that m(Y)=228.03u , m( _0^1n)=1.009u m( _2^4He)=4.003u , m( _1^1H)=1.008u

A nucleus of mass number 220 decays by alpha decay. The energy released in the reation is 5 MeV. The kinetic energy of an alpha- particle is

Initially the nucleus of radium 226 is at rest. It decays due to which and alpha particle and the nucleus of radon are created. The released energy during the decay is 4.87 Mev, which appears as the kinetic energy of the two resulted particles [m_(alpha)=4.002"amu",m_("Rn")=22.017"amu"] Kinetic energies of alpha particle & radon nucleus are respectively

Initially the nucleus of radium 226 is at rest. It decays due to which and alpha particle and the nucleus of radon are created. The released energy during the decay is 4.87 Mev, which appears as the kinetic energy of the two resulted particles [m_(alpha)=4.002"amu",m_("Rn")=22.017"amu"] Kinetic energies of alpha particle & radon nucleus are respectively