A resistor `R` has power of dissipation `P` with cell voltage `E`. The resistor is cut in equal parts and all parts are connected in parallel with same cell. The new power dissipation is

Two resistors whose value are in ratio 2 : 1 are connected in parallel with one cell. Then ratio of power dissipated is

A wire connected to a power supply of 230V has power dissipation P_(1) . Suppose the wire is cut into two equal pieces and connected parallel to the same power supply. In this case power dissipation is P_(2) . The ration (P_(2))/(P_(1)) is.

A wire when connected to 220 V mains supply has power dissipation P_1 . Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is P_2. Then P_2: P_1 is

A wire when connected to 220 V mains supply has power dissipation P_1 . Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is P_2 . Then P_2: P_1 is

A wire when connected to 220 V mains supply has power dissipation P_1 . Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is P_2 . Then P_2: P_1 is

A wire when connected to 220 V mains supply has power dissipation P_1 . Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is P_2 . Then P_2: P_1 is

A wire when connected to 220 V mains supply has power dissipation P_(1) . Now, the wire is cut into two equal pieces which are connected in parallel to same supply. Power dissipation in this case is P_(2) . Then, P_(1) : P_(2) is