In a radioactive material the activity at time `t_(1)` is `R_(1)` and at a later time `t_(2)`, it is `R_(2)`. If the decay constant of the material is `lambda`, then

Options

A. `R_(1)=R_(2)" " e^(-lambda(t_(1)-t_(2))`
B. `R_(1)=R_(2)" " e^(lambda(t_(1)-t_(2))`
C. `R_(1)=R_(2) (t_(2)//t_(1))`
D. `R_(1)=R_(2)`

Answer

A

Explanation

`R_(1)=R_(0)e^(-lambdat_(1)) & R_(2)=R_(0)e^(-6t_(2))`
`impliesR_(1)/(R_(2))=e^(-lambdat_(1))/e^(-lambdat_(2))`
`e^(-lambda(t_(1)-t_(2)))impliesR_(1)=R_(2) e^
(lambda(t_(1)-t_(2))`