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For angles of projection of a projectile...

For angles of projection of a projectile at angles `(45^(@)` – θ) and `(45^(@) + θ)`, the horizontal ranges described by the projectile are in the ratio of:

A

` 1 : 1 `

B

`2 : 3 `

C

` 1 : 2 `

D

`2 : 1 `

Text Solution

Verified by Experts

The correct Answer is:
A
For complementary angles, rnage will be same
OR
`(R^(1))/(R^2)=[[(u^(2)sin 2(45-0))/(g)]/[[u^(2) sin2(45+0))/(g)]]=(u^(2)sin(90-20))/(u^(2)sin(90+20))`
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Knowledge Check

  • For angles of projection of a projectile at angle (45^(@) - theta) and (45^(@)+ theta) , the horizontal ranges described by the projectile are in the ratio of :

    A
    `1:1`
    B
    `2:3`
    C
    `1:2`
    D
    `2:1`

  • Galileo writes that for angles of projection of a projectile at angles (45 + theta) and (45 - theta) , the horizontal ranges described by the projectile are in the ratio of (if theta le 45 )

    A
    `2 : 1`
    B
    `1: 2`
    C
    `1 : 1`
    D
    `2 : 3`

  • For angles of projection of a projectilc at angles (45 ^(@)-theta) "and" (45 ^(@)+ theta), the horizontal ranges described by the projectile are in the ratio of :

    A
    `1 :1 `
    B
    ` 2 : 3`
    C
    `1 : 2`
    D
    ` 3 : 2`

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