The momentum of a photon of energy 1 MeV in kg-m/s, will be

Options

A. 0.33 × `10^(6)`
B. ` 7 × 10^(–24)`
C. `10^(–22)`
D. ` 5× 10^(–22)`

Answer

D

Explanation

For a photon E=pc
`impliesp=(E)/(c)=(10^(6)xx1.6xx10^(-19))/(3xx10^(8))=5.33xx10^(-22)`
`kgms^(-1)`