A solution of sucrose (molar mass `342g mol^(-1)`has been produced by dissolving`68.5g`sucrose in `1000g`water .The freezing point of the solution obtained will be `(K_(f)` for `H_(2)O=1.86kgmol^(-1))`

A solution of sucrose (molar mass 342 "gmol"^(-1) ) has been produced by dissolving 68.5g sucrose in 1000g water. The freezing point of the solution obtained will be ( K_f for H_2O = 1.86 kg "mol"^(-1) )

A solution of sucrose (molar mass = 342 g mol^(-1)) has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the solution obtained will be: (K_(f) for water = 1.86 K kg mol^(-1))

A solution of sucrose (molar mass =342 g mol^(-1) ) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be ( K_(f) for water = 1.86K kg mol^(-1) )

A solution of sucrose (molar mass = 342 "g mol"^(-1) ) has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the solution obtained will be : ( K_(f) for water = 1.86 "K kg mol"^(-1) )

A solution of sucrose (molar mass =342 g mol^(-1) ) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The depression in freezing point of the solution obtained will be ( K_(f) for water = 1.86K kg mol^(-1) )

A solution of sucrose (molar mass =342) is prepared by dissolving 68.4 g in 1000 g of water. Calculate The freezing point of solution.