A body of mass `m_(1)` collides elastically with another body of mass `m_(2)` at rest. If the velocity of `m_(1)` after collision is `(2)/(3)` times its initial velocity, the ratio of their masses is `:`

A body of mass M_(1) collides elastically with another mass M_(2) at rest. There is maximum transfer of energy when :

A body of mass M_(1) collides elastically with another mass M_(2) at rest. There is maximum transfer of energy when :

A body of mass M moves with velocity v and collides elasticity with another body of mass m(M gt gt m) at rest , then the velocity of the body of mass m is

A body of mass m1 collides head on perfectly elastically with a stationary body of mass m_(2) . If velocities of m_(1) before and after the collision are v and –v/3 respectively then the value of m_(1)//m_(2) is-

A body of mass m moving with velocity vecV collides elastically with another body B of same mass which is at rest. What will be the velocities of A and B after collision?

A body of mass m_(1) is moving with a velocity V. it collides with another stationary body of mass m_(2) . They get embedded. At the point of collision, the velocity of the system.

When a body of mass m_(1) moving with uniform velocity 40 ms^(-1) collides with another body of mass m_(2) at rest, then the two together begin to move with uniform velocity of 30 ms^(-1) . The ratio of the masses (i.e., m_(1)//m_(2) ) of the two bodies will be