`sqrt[x^2y^[-9/4]]`.`[x^[-8/3]y^3]^[1/4]`

An equilateral triangle whose two vertices are (-2, 0) and (2, 0) and which lies in the first and second quadrants only is circumscribed by a circle whose equation is : (A) sqrt(3)x^2 + sqrt(3)y^2 - 4x +4 sqrt(3)y = 0 (B) sqrt(3)x^2 + sqrt(3)y^2 - 4x - 4 sqrt(3)y = 0 (C) sqrt(3)x^2 + sqrt(3)y^2 - 4y + 4 sqrt(3)y = 0 (D) sqrt(3)x^2 + sqrt(3)y^2 - 4y - 4 sqrt(3) = 0

Simplify : (8x^3-27y^3)/(4x^2-9y^2)

lim_( x to 0)(xsqrt(y^(2)-(y-x)^(2)))/({sqrt((8xy-4x^(2))+sqrt(8xy))}^(3))=

The value of f(x,y)=((x^(3)y)^((1)/(4))-(y^(3)x)^((1)/(4)))/(sqrt(y)-sqrt(x))+(1+sqrt(xy))/((xy)^((1)/(4)))xx((1+2sqrt((y)/(x))+(y)/(x))^(4) when x=9 and y=0.04

Solve the following pair of linear equations by the substitution method. (i) x+y=14 ;x- y=4 (ii) s-t=3; s/3+t/2=6 (iii) 3x-y=3;9x-3y=9 (iv) 0. 2 x+0. 3 y=1. 3 ;0. 4 x+0. 5 y=2. 3 (v) sqrt(2)x+sqrt(3)y=0;sqrt(3)x-sqrt(8)y=0 (vi) 3x/2-5y/2=-2;x/3+y/2=13/6

Solve the following pair of linear equations by the substitution method. (i) x+y=14 ;x- y=4 (ii) s-t=3; s/3+t/2=6 (iii) 3x-y=3;9x-3y=9 (iv) 0. 2 x+0. 3 y=1. 3 ;0. 4 x+0. 5 y=2. 3 (v) sqrt(2)x+sqrt(3)y=0;sqrt(3)x-sqrt(8)y=0 (vi)3x/2-5y/2=-2;x/3+y/2=13/6

Resolve the factors x^3(4y^2-9z^2)+8y^3(9z^2-x^2)+27z^3(x^2-4y^2)

The equation of the transvers and conjugate axes of a hyperbola are, respectively, x+2y-3=0 and 2x-y+4=0 , and their respective lengths are sqrt(2) and 2sqrt(3)dot The equation of the hyperbola is 2/5(x+2y-3)^2-3/5(2x-y+4)^2=1 2/5(x-y-4)^2-3/5(x+2y-3)^2=1 2(2x-y+4)^2-3(x+2y-3)^2=1 2(x+2y-3)^2-3(2x-y+4)^2=1

The value of f(x,y)=((4sqrt(x^(3)y)-4sqrt(x^(3)))/(sqrt(y)-sqrt(x))+(1+sqrt(xy))/(4sqrt(xy)))^(-2)(1+2sqrt((y)/(x))+(y)/(x))^((1)/(2)) when x=9,y=0.04

Solve the following pairs of equations by reducing them to a pair of linear equations: (i) 1/(2x)+1/(3y)=2 ; 1/(3x)+1/(2y)=(13)/6 (ii) 2/(sqrt(x))+3/(sqrt(y))=2 ; 4/(sqrt(x))-9/(sqrt(y))=-1 (iii) 4/x+3y=14 ; 3/x-4y=23 (iv) 5/(x-1)+1/