In the given `DeltaABC`,It is given that `/_B=90^@,AB=24cm and BC=7cm`.Then `cosA=?`

In the given figure DeltaABC is a right angled triangle with /_B=90^(@),AB=48cm and BC=14cm . With AC as diameter a semicircle is drawn and with BC as radius, a quadrant of a circle is drawn. Find the area of the shaded region. [Use pi=22/7 ]

In DeltaABC , right - angled at B , AB = 24 cm , BC = 7 cm . sinC , cos C

In DeltaABC , right angled at B, AB = 24 cm, BC = 7 cm. The value of cos A is :

O is the circumcentre of the isosceles DeltaABC . Given that AB = AC = 17 cm and BC = 6 cm. The radius of the circle is

In DeltaABC , right angled at B, AB = 24cm, BC = 7cm . The value of cos C is :

In DeltaABC , right - angled at B , AB = 24 cm , BC = 7 cm . sinA, cos A

In /_\\ ABC, /_B = 90^(@) , AB = 5 cm and AC = 13 cm. Then, BC = ?

In the figure , DeltaABC is right angles at B, BC=7cm and AC-AB=1cm. Find the value of cosA+sinA.