10 gm of ice cubes at `0^(@)"C"` are released in a tumbler (water equivalent 55 g) at `40^(@)"C"`. Assuming that negligible heat is taken from the surroundings, the temperature of water in the tumbler becomes nearly` "(L = 80 cal/g)"`

In a container of negligible heat capacity 200 gm ice at 0^(@) C and 100 gm steam at 100^(@) C are added to 200 gm of water that has temperature 55^(@) C. Assume no heat is lost to the surroundings and the pressure in the container is constant of 1.0atm (L_(f)=80 cal//gm,L_(v)=540cal//gm, s_(w)=1 cal//gm^(@)C) At the final temperature, mass of the total water present in the system, is

In a container of negligible heat capacity 200 gm ice at 0^(@) C and 100 gm steam at 100^(@) C are added to 200 gm of water that has temperature 55^(@) C. Assume no heat is lost to the surroundings and the pressure in the container is constant of 1.0atm (L_(f)=80 cal//gm,L_(v)=540cal//gm, s_(w)=1 cal//gm^(@)C) At the final temperature, mass os the total water present in the system, is

In a container of negligible heat capacity 200 gm ice at 0^(@) C and 100 gm steam at 100^(@) C are added to 200 gm of water that has temperature 55^(@) C. Assume no heat is lost to the surroundings and the pressure in the container is constant of 1.0atm (L_(f)=80 cal//gm,L_(v)=540cal//gm, s_(w)=1 cal//gm^(@)C) What is the final temperature of the system ?

In a container of negligible heat capacity 200 gm ice at 0^(@) C and 100 gm steam at 100^(@) C are added to 200 gm of water that has temperature 55^(@) C. Assume no heat is lost to the surroundings and the pressure in the container is constant of 1.0atm (L_(f)=80 cal//gm,L_(v)=540cal//gm, s_(w)=1 cal//gm^(@)C) Amount of the steam left in the system, is equal to

450 g water at 40^(@)C was kept in a calorimeter of water equivalent 50 g 25 g ice at 0^(@)C is added and simultaneously 5 g steam at 100^(@)C was passed to the calorimeter. The final temperature of the calorimeter. Will be (L_(ice)=80 cal // g.L_(steam) =540cal//g)

Four cubes of ice at -10^(@)C each one gm is taken out from the refrigerator and are put in 150 gm of water at 20^(@)C . The temperature of water when thermal equilibrium is attained. Assuming that no heat is lost to the outside and water equivalent of contaner is 46 gm . (Specific heat capacity of water = 1 cal//gm-^(@)C , Specific heat capacity of ice =0.5 cal//gm-^(@)C , Latent heat of fusion of ice = 80 cal//gm-^(@)C )

In a container of negligible heat capacity, 200 gm ice at 0^(@)C and 100gm steam at 100^(@)C are added to 200 gm of water that has temperature 55^(@)C . Assume no heat is lost to the surroundings and the pressure in the container is constant 1.0 atm . (Latent heat of fusion of ice =80 cal//gm , Latent heat of vaporization of water = 540 cal//gm , Specific heat capacity of ice = 0.5 cal//gm-K , Specific heat capacity of water =1 cal//gm-K) What is the final temperature of the system ?

In a container of negligible heat capacity, 200 gm ice at 0^(@)C and 100gm steam at 100^(@)C are added to 200 gm of water that has temperature 55^(@)C . Assume no heat is lost to the surrpundings and the pressure in the container is constant 1.0 atm . (Latent heat of fusion of ice =80 cal//gm , Latent heat of vaporization of water = 540 cal//gm , Specific heat capacity of ice = 0.5 cal//gm-K , Specific heat capacity of water =1 cal//gm-K) What is the final temperature of the system ?

In a container of negligible heat capacity, 200 gm ice at 0^(@)C and 100gm steam at 100^(@)C are added to 200 gm of water that has temperature 55^(@)C . Assume no heat is lost to the surrpundings and the pressure in the container is constant 1.0 atm . (Latent heat of fusion of ice =80 cal//gm , Latent heat of vaporization of water = 540 cal//gm , Specific heat capacity of ice = 0.5 cal//gm-K , Specific heat capacity of water =1 cal//gm-K) Amount of the steam left in the system, is equal to

In a container of negligible heat capacity, 200 gm ice at 0^(@)C and 100gm steam at 100^(@)C are added to 200 gm of water that has temperature 55^(@)C . Assume no heat is lost to the surrpundings and the pressure in the container is constant 1.0 atm . (Latent heat of fusion of ice =80 cal//gm , Latent heat of vaporization of water = 540 cal//gm , Specific heat capacity of ice = 0.5 cal//gm-K , Specific heat capacity of water =1 cal//gm-K) Amount of the steam left in the system, is equal to