If the focus of a parabola is `(3,3)` and its directrix is `3x-4y=2` then the length of its latus rectum is

The vertex of a parabola is at (4,3) and directrix is x-y+1=0. Then the equation of its latus rectum is

Find the coordinates of the point of intersection of the axis and the directrix of the parabola whose focus is (3,3) and directrix is 3x-4y=2. Find also the length of the latus rectum.

find the coordinates of the point of intersection of the axis and the directrix of the parabola hose focus is (3,3) and directrix is 3x-4y=2. Find also the length of the latus rectum.

Focus of a parabola is (2,3) and directrix is x-4y+t=0 and its length of latus rectum is (14)/(sqrt(17)) ,then t is equal to (t is a single digit integer)

The focus of a parabola is (1,5)and its directrix is x+y+2=0.Find the equation of parabola.Find its vertix and length of latus rectum.

Find the equation of the parabola whose focus is (3, 4) and whose directrix is 3x + 4y + 25 = 0 . Also find the length of latus rectum of he parabola .

In the following ,find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum. y^2 = 12x

In the following ,find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum. y^2 = -8x