The average value of voltage for one cycle for the function
`V=V_(0)sin omegat "for" o le t le (pi)/(omega)`
`=-V_(0)sin omegat "for" (pi)/(omega) le t le (2pi)/(omega)` is

The voltage over a cycle varies as V=V_(0)sin omega t for 0 le t le (pi)/(omega) =-V_(0)sin omega t for (pi)/(omega)le t le (2pi)/(omega) The average value of the voltage one cycle is

The voltage over a cycle varies as V=V_(0)sin omega t for 0 le t le (pi)/(omega) =-V_(0)sin omega t for (pi)/(omega)le t le (2pi)/(omega) The average value of the voltage one cycle is

The voltage over a cycle varies as V=V_(0)sin omega t for 0 le t le (pi)/(omega) =-V_(0)sin omega t for (pi)/(omega)le t le (2pi)/(omega) The average value of the voltage one cycle is

The average value of an alternating voltage V=V_(0) sin omega t over a full cycle is

The average value of an alternating voltage V=V_(0) sin omega t over a full cycle is

The average value of an alternating voltage V=V_(0) sin omega t over a full cycle is

Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

Give expression for average value of a.c. voltage V = V_(0) sin omega t over interval t = 0 to t = (pi)/(omega)

The average value of alternating current I=I_(0) sin omegat in time interval [0, pi/omega] is