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A liquid in a beaker has temperature (t)...

A liquid in a beaker has temperature (t) at timet and 0, is temperature of surroundings, then according to Newton's law of cooling the correct graph between loge (0 - 0) and t is :- ►log.(0-0) 0->log (0-6) > t ->log.(0-0) log.(0-0) -

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