What is the equation of the circle which passes through the points (3,-2) and (-2, 0) and having its centre on the line 2x-y-3=0?

Find the equation of the circle which passes through the points (3, -2), (-2, 0) and has its centre on the line 2x - y =3.

Find the equation of the circle which passes through the points (3, -2), (-2, 0) and has its centre on the line 2x - y =3.

Find the equation of the circle which passes through the points (3,-2) and (-2,0) and the center lies on the line 2x-y=3

Find the equation of the circle which passes through the points (3,-2)a n d(-2,0) and the center lies on the line 2x-y=3

Find the equation of the circle which passes through the points (3,-2)a n d(-2,0) and the center lies on the line 2x-y=3

Find the equation of the circle, which passes through the points (2, - 3) and (3, - 2) and has its centre on the line 2x-3y = 8.

Find the equation of the circle which passes through the points (-1,2) and (3,-2) and whose centre lies on the line x-2y=0

Find the equation of the circle which passes through the points (1, 3 ) and (2, - 1 ) , and has its centre on the line 2x + y - 4 = 0

Find the equation of the circle which passes through the points (-1,2) and (3,-2) and whose centre lies on the line x-2y=0 .

Solve the following:Find the equation of the circle which passes through the points (2,1) and (-2,3) and has centre on the line x+y+4=0