A circle touches the side BC of `DeltaABC` at P and touches AB and AC produced at Q and R respectively. Prove that AQ=1/2(Perimeter of `DeltaABC)`.

A circle is touching the side BC of Delta ABC at P and touching AB and AC produced at Q and R respectively Prove that AQ=(1)/(2) (Perimeter of Delta ABC)

A circle is touching the side BC of DeltaABC at P and touching AB and AC extended at Q and R respectively. Prove that, AQ=1/2 (permeter of DeltaABC) .

A circle is touching the side BC of ABC at P and touching AB and AC produced at Q and R respectively.Prove that AQ=(1)/(2)(Perimeter of ABC)

A circle touches the side BC of a Delta ABC at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of Delta ABC = 26.4 cm, then the length of AQ is:

A circle is touching the side BC of /_\ABC at P and touching AB and AC produced at Q and R are respectively. Prove that AQ=1/2(AB+BC+CA)=1/2(Perimeter of /_\ABC) .

A circle is touching the side BC of a triangle ABC at point P and touching AB and AC produced at Q and R respectively. Prove that AQ=(1)/(2)("perimeter of "triangle ABC).

A circle touches the side BC of Delta ABC at F and touches AB and AC at D and E, respectively. If AD = 8 cm, then find the perimeter of Delta ABC .

A circle touches the side BC of DeltaABC at D and AB and aC are produced to E and F, respectively. If AB=10cm, AC=8.6 cm and BC=6.4 cm then BE=?