If `sum_(r=1)^n r(r+1)(2r+3)=a n^4+b n^3+c n^2+d n+e ,` then `a-b=d-c` `e=0` `a , b-2//3,c-1` are in A.P. `(b+d)//a` is an integer

If sum_(r=1)^n r(r+1)(2r+3)=a n^4+b n^3+c n^2+d n+e , then (a) a-b=d-c (b) e=0 (c) a , b-2//3, c-1 are in A.P. (d) (b+d)//a is an integer

If sum_(r=1)^n r(r+1)(2r+3)=a n^4+b n^3+c n^2+d n+e , then (a) a-b=d-c (b) e=0 (c) a , b-2//3, c-1 are in A.P. (d) (b+d)//a is an integer

If sum_(r=1)^n r(r+1)(2r+3)=a n^4+b n^3+c n^2+d n+e , then a. a-b=d-c b. e=0 c. a , b-2//3,c-1 are in A.P. d. c/a is an integer

sum_(r=1)^( If )r(r+1)(2r+3)=an^(4)+bn^(3)+cn^(2)+dn+e then a-b=d-ce=0a,b-2/3,c-1 are in A.P.(b+d)/a is an integer

If sum_(r=1) (r-1)(r+1)=((n+a)(n+b)(n+c))/3 , a

sum_(r=1)^(n)r(r+1)=((n+a)(n+b)(n+c))/(3) then

If sum_(r=1)^(n) r(r+1) = ((n+a)(n+b)(n+c))/(3) , where a gt b gt c , then

sum_(r=0)^n((-1)^r*C_r)/((r+1)(r+2)(r+3))=1/(a(n+b)), then a+b is

If sum_(r=1)^(n)r^(3)((C(n,r))/(C(n,r-1)))=14^(2) then n=

Find sum of sum_(r=1)^n r . C (2n,r) (a) n*2^(2n-1) (b) 2^(2n-1) (c) 2^(n-1)+1 (d) None of these