A body of mass `m` rises to a height `h=R//5` from the earth's surface where `R` is earth's radius. If `g` is acceleration due to gravity at the earth's surface, the increase in potential energy is

A body of mass m rises to height h = R/5 from the earth's surface, where R is earth's radius. If g is acceleration due to gravity at earth's surface, the increase in potential energy is

A body of mass m rises to a height h=R/5 from the surface of earth. If g is the acceleration due to gravity at the surface of earth, the increase in potential energy is (R = radius of earth)

A particle is taken to a height R above the earth's surface, where R is the radius of the earth. The acceleration due to gravity there is

A body of mass m is taken from the Earth's surface to a height equal to the radius R of the earth. If g is the acceleration to gravity at the surface of the Earth, then find the change in the potential energy of the body .......

A body of mass m is raised from the surface of the earth up to a height equal to the radius R of the earth. If the acceleration due to gravity on the earth's surface is g , prove that the potential energy of the body has increased by 1/2 mgR.

Calculate the work required to raise a body of mass m to a height h just above the earth's surface. Radius of the earth is R and acceleration due to gravity at the earth's surface is g.

An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

Periodic time of a satellite revolving above Earth's surface at a height equal to R, radius of Earth, is : [g is acceleration due to gravity at Earth's surface]