Two trains starting simultaneously from P&Q towards Q and P resp at 8 am. They cross each other at 12 noon. Train starting from Q, Thereafter takes 6 hours to reach P. On a particular day, the train starting from P, reduced its speed and arrived at Q, 200 minutes late. At what time did the trains cross each other on that day?

Explanation

`4V_1=6V_2`

`V_2=(V_1)/3`

`V_1t=V_2 4`

`V_1=8/3h`

lime(Normal)=`4+8/3=20/3h`

Specific lime=`20/3+200/60=10h`

`d=V_1*20/3=V*10`

`V_1=(2V_2/3)`

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