Mrs. Kapoor has certain sum of money to buy fruits. She can buy `n` mangoes at Rs.1.60 each and have Rs 0.80 left. Alternatively, she can buy `(n+10)` apples at Rs0.70 each and have Rs0.10 left. If Mrs. Kapoor buys 3 mangoes and uses the rest of the money to buy apples, then

Explanation

Let Mrs. Kapoor has `x` money in rupees.

Then, `1.60n+0.8 = x->(1)`

`0.7(n+10)+0.10 = x->(2)`

From (1) and (2),

`1.6n+0.8 = 0.7n+7+0.10`

`=>0.9n = 6.3=> n = 7`

Putting value of `n` in (1),

`1.6(7)+0.8 = x`

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