Find the equation of the tangent to the circle `x^2+y^2+4x-4y+4=0` which makes equal intercepts on the positive coordinates axes.

The equation of the tangent to the circle x^2 + y^2 + 4x - 4y + 4 = 0 which makes equal intercepts on the positive coordinate axes is:

The equation of the tangent to the circle x^(2)+y^(2)+4x-4y+4=0 which make equal intercepts on the positive coordinates, is

The equation of the tangent to the circle x^2+y^2+4x-4y+4=0 which make equal intercepts on the positive co-ordinates axes is given by

The equation of the tangent of the circle x^(2)+y^(2)+4x-4y+4=0 which make equal intercepts on the positive coordinate axes,is -x+y=2x+y=2sqrt(2)x+y=4x+y=8

The equation of the tangent to the circle x^2 + y^2+4x- 4y + 4 =0 , which makes equal intercepts on the positive axes, is :

The equation of the tangent to the circle x^(2) + y^(2) + 4x - 4y + 4 = 0 which makes equal intercepts on the coordinates axes in given by

Find the equation of the tangent to the circle x^2+y^2-4x-6y-12=0 at (-1,-1)