In the figure O is the center of a circle and PO bisects `/_APD`

In the given figure O is the centre of a circle and PO bisects angleAPD . Prove that AB = CD

In the figure, O is the center of the circle and BO is the bisector of /_ ABC show that AB=BC

In the figure, O is the centre of a circle and diameter AB bisects the chord CD at a point E such that CE = ED = 8 cm and EB = 4 cm. The radius of the circle is . . . . .

In the figure,O is the center of the circle and BO is the bisector of angle ABC show that AB=BC

In Figure, O is the centre of a circle and P O BISECTS /_A P D . Prove that A B=C D

In the adjoining figure, O is the center of the circle and AC is a diameter of it If DC||EB, angleAOB=80^(@)andangleACE=10^(@) , then find the value of angleBED.

In the adjoining figure ,O is the center of the circle and AB is a diameter. If angleAOD=140^(@)andangleCAB=50^(@) , then find value of angleBED

In the given figure O is the center of circle and its radius is 10 cm. If BC is tangent and CA is a secant. If AC = 36 cm., then area of DeltaABC ?