If wavelength `4500 Å` and `6000 Å` are found to be missing in the reflected spectrum in thin air film interference, the thickness of the film for normal incidence is nearly

For observing interference in thin films with a light of wave length lambda the thickness of the film :

A parallel beam of white light is incident on a thin film of air of uniform thickness. Wavlength 7200 Å and 5400 Å are observed to be missing from the spectrum of reflected light viewed normally. The other wavelength in the visible region missing in the reflected spectrum is

A parallel beam of white light is incident on a thin film of air of uniform thickness. Wavlength 7200 Å and 5400 Å are observed to be missing from the spectrum of reflected light viewed normally. The other wavelength in the visible region missing in the reflected spectrum is

Consider a case of thin film interference as shown.Thickness of film is equal to wavelength of light in mu_(2)

Light of wavelength 6000 Å falls on a plane reflecting surface. The reflected wavelength is.

White light incident perpendicular on a soap film gets reflected . It has an interference maximum at 5800 Å and a minimum at 4200 Å in a visible spectrum. If there is no minimum in between the two bands, find the thickness of the soap film. Take refractive index of film = 4//3 .

The wavelength of the photons are 4500 Å and 6000 Å. The ratio of their energies is

Light of wavelength 6000Å falls on a plane reflecting surface. The reflected wavelength is

A thin film having refractive index mu" = 1.5" has air on both sides. It is illuminated by white light falling normally on it. Analysis of the reflected light shows that the wavelengths 450 nm and 540 nm are the only missing wavelengths in the visible portion of the spectrum. Assume that visible range is 400 nm to 780 nm. (a) Find thickness of the film. (b) Which wavelengths are brightest in the interference pattern of the reflected light?