The rate law for the reaction
`RCl + NaOH(aq) rarr ROH + NaCl` is given by
Rate `= k[RCl]`. The rate of the reaction will be

The rate law for the reaction, RCl + Na (a) rarr ROH + NaCl is given by, rate = K_(1) [RCl]. The rate of the reaction will be -

The rate law for the reaction RCl + NaOH(aq) to ROH + NaCl is given by Rate =K_1[RCl] . The rate of the reaction will be

The rate law for the reaction RCl+Na(aq.)rarrROH+NaCl is given by, rate =K_(1)[RCl]. The rate of the reaction will be :

The rate for the reaction, RCl+NaOH(aq)rarrROH+NaCl is given by rate= K_1[RCl] . The rate of the reaction is:

The rate for the reaction: RCl+NaOH(aq)rarr ROH+NaCl is given by rate = k_(1)[RCl] The rate of the reaction is: (A) Doubled on doubling the concentration of "NaOH (B) Halved on reducing the concentration of "RCl" to half (C) Decreased on increasing the temperature of reaction (D) Unaffected by increasing the temperature of the reaction