In triangle ABC, the line BD is perpendicular to AC.The area of triangle ABC is `40 cm^2`. BD = (x+1)cm , AD = (x+6)cm , CD = (x+2)cm

In triangle ABC,the line BD is perpendicular to AC.The area of triangle ABC is 40cm^(2).BD=(x+1)cm,AD=(x+6)cm,CD=(x+2)cm

In triangle ABC, AB=AC and BD is perpendicular to AC. Prove that : BD^(2)-CD^(2)=2CDxxAD

A triangle ABC is such that AD is perpendicular to BC and E is a point on DC. Also. Given that BD= 2 cm, DE = 4 cm, and EC = 8 cm. Find the ratio of the areas of Delta ABC , Delta ADE and Delta AEC.

In a triangle ABC, angleBCA = 90^(@) and CD is perpendicular to AB. If AD = 4 cm and BD = 9 cm, then the value of DC will be

In triangle ABC,AD=BD=CD (See figure). What is x?

In an isosceles triangle ABC with AB=AC,BD is perpendicular from B to the side AC. Prove BD^(2)-CD^(2)=2CD.AD

In an isosceles triangle ABC with AB = AC, BD is perpendicular from B to side AC. Prove that BD^(2)-CD^(2)=2CD.AD

If triangle ABC , AC = 13 cm. then find the length of the median BD.

In traingle ABC , AD bisects angle A , AB = 5 cm, BD = 8 cm and DC = 6 cm then AC = ……….cm.